PivotOJ

Hungry Cow

시간 제한: 6000ms메모리 제한: 1024MB출처: USACO 2023 February PlatinumBOJ 27840

문제

Bessie is a hungry cow. Each day, for dinner, if there is a haybale in the barn, she will eat one haybale. Farmer John does not want Bessie to starve, so some days he sends a delivery of haybales, which arrive in the morning (before dinner). In particular, on day did_i, Farmer John sends a delivery of bib_i haybales (1di10141\leq d_i \leq 10^{14}, 0bi1090\leq b_i \leq 10^9).

Process UU (1U1051\le U\le 10^5) updates as follows: Given a pair (d,b)(d, b), update the number of haybales arriving on day dd to bb. After each update, output the sum of all days on which Bessie eats haybales modulo 109+710^9+7.

입력

UU, followed by UU lines containing the updates.

출력

The sum after each update modulo 109+710^9+7.

예제

예제 1

입력
3
4 3
1 5
1 2
출력
15
36
18

예제 2

입력
9
1 89
30 7
101 26
1 24
5 1
60 4
5 10
101 0
1 200
출력
4005
4656
7607
3482
3507
3753
4058
1107
24531
코드를 제출하려면 로그인하세요.