PivotOJ

Folding a Cube

시간 제한: 1000ms메모리 제한: 512MB출처: ICPC Rocky Mountain Regional 2019BOJ 17876

문제

It is well known that a set of six unit squares that are attached together in a “cross” can be folded into a cube.

But what about other initial shapes? That is, given six unit squares that are attached together along some of their sides, can we form a unit cube by folding this arrangement?

입력

Input consists of 6 lines each containing 6 characters, describing the initial arrangement of unit squares. Each character is either a ., meaning it is empty, or a # meaning it is a unit square.

There are precisely 6 occurrences of # indicating the unit squares. These form a connected component, meaning it is possible to reach any # from any other # without touching a . by making only horizontal and vertical movements. Furthermore, there is no 2 × 2 subsquare consisting of only #. That is, the pattern

##
##

does not appear in the input.

출력

If you can fold the unit squares into a cube, display can fold. Otherwise display cannot fold.

예제

예제 1

입력
......
......
######
......
......
......
출력
cannot fold

예제 2

입력
......
#.....
####..
#.....
......
......
출력
can fold

예제 3

입력
..##..
...#..
..##..
...#..
......
......
출력
cannot fold

예제 4

입력
......
...#..
...#..
..###.
..#...
......
출력
can fold
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