PivotOJ

Copycat Catcher

시간 제한: 3000ms메모리 제한: 1024MB출처: GCPC 2024BOJ 32479

문제

Your university recently established the Graduate Code Plagiarism Control (GCPC) initiative to get hold of the ever-increasing load on the graders for the computer science assignments. Currently, the graders need to check the code of assignments manually for plagiarism. The GCPC aims to simplify this part of the graders' jobs by performing the plagiarism checks automatically.

Code consists of tokens separated by spaces. Tokens are strings of alphabetical letters, numerals, and brackets. If a token consists of only a single alphabetical letter (upper or lowercase), it is a variable in the code.

The GCPC wants the plagiarism checker to compare query pieces of code to a reference code. Specifically, it should check whether each query could have been obtained by selecting a contiguous string of tokens from the reference and consistently renaming variables.

Variables are consistently renamed if no two occurrences of the same variable are renamed to different variables, and if no two different variables are renamed to the same variable.

The GCPC has asked you to develop the plagiarism checker.

입력

The input consists of:

  • A description of the reference, consisting of:
    • One line containing an integer nn (1n20001\leq n \leq 2\,000), the number of tokens in the reference.
    • One line containing nn tokens, each consisting only of the characters 'a'-'z', 'A'-'Z', '0'-'9', '(' and ')'.
  • An integer qq (1q20001 \leq q \leq 2\,000), the number of queries.
  • 2q2\cdot q lines, each two lines in the same format as the reference.

It is guaranteed that each query as well as the reference consist of at most 20002\,000 characters (excluding spaces). Tokens are separated by single spaces.

출력

For each query, output "yes" if the query could have been obtained from the reference, and "no" otherwise.

예제

예제 1

입력
9
for i in range(10) do print i j end
4
3
print j i
2
do print
6
k in range(10) do print k
6
k in range(10) do print j
출력
yes
yes
yes
no

예제 2

입력
5
i is i times j
7
5
i is i times j
5
a is a times b
5
j is j times c
5
a is i times j
5
j is i times j
5
0 is 0 times j
5
i is i times i
출력
yes
yes
yes
no
no
no
no

예제 3

입력
5
A 1 ( ) b
4
2
b 2
2
b 1
3
1 ) (
5
a 1 ( ) F
출력
no
yes
no
yes
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