Kinky Word Searches
문제
You're probably familiar with regular word searches, where you're presented with a grid of letters and a word to find. The word can be in a straight line horizontally, vertically, or diagonally (and perhaps backwards in any of those directions). For example, here is a grid of letters:
Figure 1: A word search grid
The word "JAVA" can be found going from the bottom right corner diagonally upwards.
In a kinky word search the path that spells out the word can have one or more "kinks" -- places where the path changes direction. For example, in the given grid you can spell the word "PYTHON" with kinks (one each at the T, H and O):
Figure 2: A kinky spelling of "PYTHON"
Adding kinks allows letters to be reused -- the word "CPLUSPLUS" can be found in the upper right corner of the grid (with kinks). However you cannot stay on a letter twice in a row, so you cannot spell the word "HASKELL" in this grid (though you can find at least more common programming languages). Your task is to see if the spelling of a word with a certain number of kinks is possible or not.
입력
Input begins with a line containing two positive integers and (, the number of rows and columns in the grid. After this are rows of uppercase characters. Letters are separated by a space. After the grid are two lines: The first line is an integer , the number of kinks. The second line contains an uppercase word to look for, with maximum length .
출력
Output either the word YES if it is possible to spell the given word with exactly kinks on the grid provided, or NO if it is not.
예제
예제 1
5 5 L M E L C C A K U P D O V S Y R N L A T P G O H J 0 JAVA
YES
예제 2
5 5 L M E L C C A K U P D O V S Y R N L A T P G O H J 3 PYTHON
YES
예제 3
5 5 L M E L C C A K U P D O V S Y R N L A T P G O H J 4 PYTHON
NO