PivotOJ

Grinding Gravel

시간 제한: 4000ms메모리 제한: 1024MB출처: BAPC 2022BOJ 25998

문제

During the renovation of your garden, you decide that you want a gravel path running from the street to your front door. Being a member of the Boulders And Pebbles Community, you want this path to look perfect. You already have a regular grid to put the gravel in, as well as a large container of gravel containing exactly as much as the total capacity of the grid.

There is one problem: the gravel does not yet fit perfectly into the grid. Each grid cell has the same (fixed) capacity and every piece of gravel has a certain weight. You have a grindstone that can be used to split the stones into multiple pieces, but doing so takes time, so you want to do a minimal number of splits such that the gravel can be exactly distributed over the grid.

As an example, consider the first sample case. There are three grid cells of size 88, which can be filled as follows. Put the stones of weight 22 and 66 in the first cell. Now grind the stone of weight 77 into two pieces of weight 33 and 44. Then the other two grid cells get filled by weights 3,53, 5 and 4,44, 4 respectively.

입력

The input consists of:

  • One line with two integers nn and kk (1n1001 \leq n \leq 100, 1k81 \leq k \leq 8), the number of pieces of gravel and the capacity per grid cell.
  • One line with nn integers w1,,wnw_1, \dots, w_n (1wi1061 \leq w_i \leq 10^6 for all ii), the weight of each piece of gravel.

It is guaranteed that w1+w2++wnw_1 + w_2 + \dots + w_n is a multiple of kk.

출력

Output the minimal number of times a stone needs to be split into two, such that all the pieces of gravel can be used to fill all the grid cells perfectly.

예제

예제 1

입력
5 8
2 4 5 6 7
출력
1

예제 2

입력
2 5
12 13
출력
4
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